Q 37 when a metal with work function of 0.6 eV is illuminated with the light of 2 eV, the necessary stopping potential for the metal will be
(a) 2.6 V                  (b) 3.6 V
(c) 0.8 V                  (d) 1.4 V

Dear student,Vo(stopping potential)=E-Woe=2eV-0.6eVe=1.4VRegards

  • 1
What are you looking for?