Q 37 when a metal with work function of 0.6 eV is illuminated with the light of 2 eV, the necessary stopping potential for the metal will be (a) 2.6 V (b) 3.6 V (c) 0.8 V (d) 1.4 V Share with your friends Share 0 Decoder_2 answered this Dear student,Vo(stopping potential)=E-Woe=2eV-0.6eVe=1.4VRegards 1 View Full Answer