Q.4 doubt plz solve it
Dear Student
Rate of formation of NH3 = 1/2 x d[NH3]/dt
rate od disappearance of H2 = -1/3 X d[H2]/dt
So, equating both
d[NH3]/dt = -2/3 x d[H2]/dt = -2/3 x (-0.3 x 10-4 ) = 2 x 10-5 mol/sec
Hence, (a) is the correct option.
Regards
Rate of formation of NH3 = 1/2 x d[NH3]/dt
rate od disappearance of H2 = -1/3 X d[H2]/dt
So, equating both
d[NH3]/dt = -2/3 x d[H2]/dt = -2/3 x (-0.3 x 10-4 ) = 2 x 10-5 mol/sec
Hence, (a) is the correct option.
Regards