Q.4 doubt plz solve it

Dear Student
Rate of formation of NH3 = 1/2  x  d[NH3]/dt
rate od disappearance of  H2 = -1/3  X  d[H2]/dt
So, equating both
d[NH3]/dt =  -2/3  x d[H2]/dt = -2/3  x (-0.3 x 10-4 )   =   2 x 10-5 mol/sec

Hence, (a) is the correct option.

Regards

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