Q 57

​Q57. The surface of metal with work function $\mathrm{\varphi }$ is illuminated by electromagnetic radiation whose electric field component is E = a (1 + cos$\mathrm{\omega }$t) cos​$\mathrm{\omega }$t. Then maximum kinetic energy of photoelectron liberated from surface is (here ​$\mathrm{\omega }$ > ​$\mathrm{\omega }$ ₀)

   (a) $\frac{h}{2\mathrm{\pi }}$ $\mathrm{\omega }$ – ​$\mathrm{\varphi }$                                          (b) ​$\frac{{\mathrm{h\omega }}_0}{2\mathrm{\pi }}-\mathrm{\varphi }$


   (c) ​$\frac{\mathrm{h}\left(\mathrm{\omega }+ {\mathrm{\omega }}_0\right)}{2\mathrm{\pi }}-\mathrm{\varphi }$                                  (d) ​​ ​$\frac{\mathrm{h}\left(\mathrm{\omega }- {\mathrm{\omega }}_0\right)}{2\mathrm{\pi }}-\mathrm{\varphi }$