Q 59 Electrochemistry

​Q59. A Daniel Cell is made at 25°C by connecting Zn / Zn⁺² (0.1 M, 1 litre ) & Cu / Cu⁺² (0.9 M, 1 litre ) electrode. The cell is discharged till its emf reaches 1.10 volt, then it is charged (reversing the discharge process ) by passing 0.6 F charge.

   $$\begin{gathered} [\mathbf{ }\mathbf{Given}\mathbf{ }\mathbf{:} \mathrm{E}{°}_{\mathrm{Zn} /{\mathrm{Zn}}^{+2}} =0.76 \mathrm{V}, \\ \mathrm{E}{°}_{\mathrm{Cu} /{\mathrm{Cu}}^{+2} }=-0.34 \mathrm{V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}} \\ = 0.06, \log 2 = 0.30 ] \end{gathered}$$

           Select the incorrect option is.

    (1) Concentration of Zn⁺² becomes 1 M when EMF reach 1.10 volt.

    (2) Concentration of Cu⁺² becomes 0.5 M when EMF reach 1.10 volt.

    (3) EMF of the cell just after charging is 1.118 volt

    (4) After charging concentration of Cu⁺² becomes 0.8 volt.