Q 6
Ans x=13 cm , 40 cm2
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Q.6. In the given figure, AD = BC = 5 cm, AB = 7 cm. The parallel sides AB, DC are 4 cm apart. DC = x cm. Find x and the area of the trapezium ABCD,

Dear Student,



In the right angle triangle ADE,DE2=AD2-AE2= 52-42=25-16=9DE = 3 cmTherefore DC = 3+7+3 = 13cmArea of trapezium ABCD = 12×AE×AB+DC=12×4×7+13=12×4×20=40 cm2

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