Q.66. CsBr has B.C.C structure with edge length 4.3. The shortest inter ionic distance in betwee C s + a n d B r - is - (a) 3.72 (b) 1.86 (c) 7.44 (d) 4.3 Share with your friends Share 1 Shyam Prasad V answered this 1 View Full Answer Arjuna Verma answered this FOR NEAREST NEIGHBOUR DISTANCE ( (3)^1÷2)×a÷2 =3.71 -2