Q 67 A positive charge of 2 0×10-7 coulomb is placed at a distance of 0 15 m from - Physics - Electric Charges And Fields

Question

Q 67 A positive charge of 2 0 × 10 - 7 coulomb is placed at a
distance of 0 15 m from another positive charge of 8 0 × 10 -
7 coulomb At what point on the line joining them is the electric
field zero ?

[Ans 0 05 m from 2 0 × 10 - 7 ]

Sakshi Kanwar · Accepted Answer

Dear Student

two charges q1=2×10-7C q2=8×10-7Cthey are 0
15m apartThe point where Enet is zero
Electric field due to charge q1=Kq1r2Electric field due to q2=Kq2(0
15-r)2q1/q2=r2(0 15-r)28×10-72×10-7=r2(0 15-r)2r/0
15-r=2r=0
05mHope this information will clear your doubts about topic
  If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible
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Q.67. A positive charge of 2 . 0 × 10 - 7 coulomb is placed at a distance of 0.15 m from another positive charge of 8 . 0 × 10 - 7 coulomb. At what point on the line joining them is the electric field zero ? [Ans. 0.05 m from 2 . 0 × 10 - 7 ]

Q.67. A positive charge of $2.0 \times 10^{- 7}$ coulomb is placed at a distance of 0.15 m from another positive charge of $8.0 \times 10^{- 7}$ coulomb. At what point on the line joining them is the electric field zero ?

[Ans. 0.05 m from $2.0 \times 10^{- 7}$ ]