Q.81. The solution of the equation 3 [ x ] + x 2 = 6 ,   x > 0 ([ . ] denotes the greatest integer function)
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Dear student

We have, 3[x]+[x2]=6[x2]+3x-6=0x=-b±b2-4ac2ax=-3±9-41-62x=-3±9+242x=-3±332Please recheck your question,because options are matching with the question.
Regards

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