Q 9:

9. A particle is projected with a velocity of 10 m/s at an angle of 75o with the horizontal. The value of 'X' for the ball to return to its initial point of projection is. 


A   2 . 5 3 B   5 m C   2 . 5   m   D   3 m

Dear Student ,
If in this question we apply the relation to find the horizontal range we can write that ,

X=u2sin2θg=100×sin 150°10=10×sin 150°=5 mThus here the correct option is B .
Regards

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