Q. A block of mass m = 1/3 kg is kept on a rough horizontal plane. Friction coefficient is $\mu$= 0.75. The work done by minimum force required to drag the block along the plane by a distance 5 m, is W joule, then find the value of W.  

The minimum force required to pull the object upwards is ,

So here the work done will be ,
W = Fs cos$\theta$
$$\begin{gathered} Here the given values are , s=5 m ,\mu =0.75 and m=\frac{1}{3}kg \\ but the value of inclination that is \theta is not given . \\ So kindly put the value of \theta in the equation and get the result . \end{gathered}$$