Q. A homozygous recessive with cd genes was crossed with dominant (+ +). If their hybrid is test crossed and the following result was obtained 
+ +  -   900 
cd    -   880
+d   -   115
+c   -   105
than what will be the distance between genes c and d. 
  1. 5.75 unit
  2. 11 unit
  3. 44 unit
  4. 90 unit

Q. Two genes a and b are linked and show 30% recombination. If ++/++ individual married with ab/ab then the types and proportion of gametes in  F 1  will be : -
  1. ++ 35% : ab : 35% : +a 15% : +b 15%
  2. ++15%  : ab : 15% : +a 35% : +b 35%
  3. ++ 35% : ab : 15% : +a 35% : +b 15%
  4. ++ 15% : ab : 35% : +a 15% : +b 35%

Dear student

Please refer the solution below for the said query

Q10.

The distance between c and d will be 11 map units.

The simplest way to solve this problem is 



Kindly post next question in separate thread.

Hope this information clears your doubt about the topic.

Regards

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