Q Calculate P2 using log book 17 33×1032 303×1×8 314×300=log 15 15×106P2 - Chemistry -

Question

Q Calculate P 2 using log book
17 33 × 10 3 2 303 × 1 × 8 314 × 300 = log
  15 15 × 10 6 P 2

Ashish Khanna · Accepted Answer

Dear Student

17 33 ×1032 303 × 1× 8
314 ×300 = log 15
15 × 106P2                                      3
017 =log 15
15 × 106P2                                               P2 = log 15
15 × 1063
017                                                    = log 15
15  + log1063
017                                                     = 1
18 + 63
017                                                     = 7
183
017                                                     =2
38

So, P2 = 2 38

Regards

Q Calculate P 2 using log book 17 . 33 × 10 3 2 . 303 × 1 × 8 . 314 × 300 = log 15 . 15 × 10 6 P 2

Q Calculate $P_{2}$ using log book
$\frac{17.33 \times 10^{3}}{2.303 \times 1 \times 8.314 \times 300} = \frac{\log 15.15 \times 10^{6}}{P_{2}}$