Q Calculate the enthalpy of combustion of B2H6 from the following data: Bs+3O2g→2B2O3s∆fH=-2546 0 kJmol-1H2g+1/2O2g→H2Ol∆fH=-286 0 kJmol-1H2Ol→H2Ol∆fH=+44 0 kJmol-1∆Bs+3/2H2g→1/2B2H6g∆fH=+18 - Chemistry - Thermodynamics

Question

Q Calculate the enthalpy of combustion of B 2 H 6 from the
following data:
B s + 3 O 2 g → 2 B 2 O 3 s ∆ f H = - 2546 0   k J
m o l - 1 H 2 g + 1 / 2 O 2 g → H 2 O l ∆ f H = - 286 0
  k J m o l - 1 H 2 O l → H 2 O l ∆ f H = + 44 0
  k J m o l - 1 ∆ B s + 3 / 2 H 2 g → 1 / 2 B 2 H
6 g ∆ f H = + 18 0   k J m o l - 1

Bharti Paliwal · Accepted Answer

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