Q. Determine final pressure after the valve is left opened for a long time in the apparatus represented in figure. Assume that the temperature is fixed at 300 K. Under the given conditions assume no reaction of CO &  O 2 .

Dear Student,


We know that, Pfinal = P1V1 +P2V2VfinalVfinal = V1 +V2         = 2L+1L         = 3LNow, Pfinal = 2.463×2+4.926×13                    =3.284 atm

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Taking each gas seperately and applying charles law(p1v1=p2V2) where v2=3 in both the cases. Now since O2 and CO are not reactive...so applying Law of partial pressure(Ptotal=P1+P2......) we are getting the right answer.....😊
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