Q. Electromagnetic radiations described by the equation-
E=100{sin(2  ×   10 15 )t + sin(6.28  ×   10 15 )t}V/m are incident on a photosensitive surface having work function 1.5eV. The maximum kinetic energy of photoelectrons will be -
  1. 0.125 eV
  2. 2.625 eV
  3. 4.125 eV
  4. 6.125 eV

Dear Student,frequency of the wavef=2*1015 Hzenergy of the photon E=hfmaximum KE  of the photoelectron=hf-1.5eV=4.136*10-15*2*1015-1.5=6.772eVRegards

  • -5
What are you looking for?