Q). Evaluate the following pls s e c 70 ° sin 20 ° + cos 20 ° cos e c 70 ° Share with your friends Share 0 Shruti Tyagi answered this Dear student, We have,sec70°sin20°+cos20°cosec70°we know that sec90-θ=cosecθ and cosec90-θ=secθ= sec90-20°sin20°+cos20°cosec90-20°=cosec20°sin20°+cos20°sec20°=1sin20°×sin20°+cos20°×1cos20°=1+1=2 Regards 0 View Full Answer