Q). Evaluate the following pls
s e c   70 °   sin   20 ° + cos   20 °   cos e c   70 °

Dear student,


We have,sec70°sin20°+cos20°cosec70°we know that sec90-θ=cosecθ and cosec90-θ=secθ= sec90-20°sin20°+cos20°cosec90-20°=cosec20°sin20°+cos20°sec20°=1sin20°×sin20°+cos20°×1cos20°=1+1=2

Regards

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