Q f = 1R →1R defined by f(x) = a2xa2x+2 Show that f(x) + f(1-x) = 1 - Maths - Relations and Functions

Question

Q f = 1R → 1R defined by f(x) = a 2 x a 2 x + 2
Show that f(x) + f(1-x) = 1

Aarushi Mishra · Accepted Answer

Dear studentYour question is wrong
 Please check it againfx=a2xa2x+2f1-x=a21-xa21-x+2f1-x=a2-2xa2-2x+2am-n=amanf1-x=a2a2xa2a2x+2f1-x=a2a2xa2+2a2xa2xf1-x=a2a2+2a2xNowfx+f1-x=a2xa2x+2+a2a2+2a2xfx+f1-x=a2
a2x+a2x 2a2x+a2x a2+2a2a2x+2a2+2a2xfx+f1-x=a2 a2x+a2x 2a2x+a2x
a2+2a2a2x+2a2+2a2xfx+f1-x=2a2 a2x+2a2x
2a2x+2a2a2x+2a2+2a2xfx+f1-x=2a2 a2x+2a2x
2a2x+2a2a2x+2a2+2a2xWe cannot simplify from here futher to get 1
Check your questionRegards

Q. f = 1R → 1R defined by f(x) = a 2 x a 2 x + 2 Show that f(x) + f(1-x) = 1

Q. f = 1R $\to$ 1R defined by f(x) = $\frac{a^{2 x}}{a^{2 x} + 2}$
Show that f(x) + f(1-x) = 1