Q Find ∠ A B C , ∠ A D E , ∠ B C D . Share with your friends Share 0 Shruti Tyagi answered this Dear Student, AD is diameter of circlein △ADE∠AED=90° --angle in semi circle is 90°sum of angles of triangle is 180⇒∠AED+∠EAD+∠ADE=180⇒60+90+∠ADE=180⇒∠ADE=180-150⇒∠ADE=30Now ABCD is a cyclic quadrilateral as its 4 vertex touches the circumfrence of circlesum of opposite angles of cyclic quadrilateral is 180⇒∠CDA+∠ABC=180⇒70+∠ABC=180⇒∠ABC=180-70⇒∠ABC=110Again in △ACD,∠ACD=90° --Angle in semi circlenow sum of 3 angles of triangle is 180⇒∠ACD+∠DAC+∠ADC=180⇒90+∠DAC+70=180⇒∠DAC=180-160⇒∠DAC=20Now ∠DAB=∠DAC+∠CAB∠DAB=20+30⇒∠DAB=50Sum of opposite angles of cyclic quadrilateral is 180∠DAB+∠BCD=180⇒50+∠BCD=180⇒∠BCD=130 Regards, 1 View Full Answer Kartikeya answered this Tough question yaar -2 Dim answered this ADE 30 0 Saketh answered this angle bcd=90 (angles near the radius =any angle on any part of the circle 0 Dim answered this ABC is 80 0 Dim answered this BCD 160 -1