Q. Find k if one of the zeroes of (k-1)(x2+kx+1) is -3 Share with your friends Share 0 Saksham Tolani answered this Dear Student, We have,px = (k-1)(x2+kx+1), as the given polynomialSince, -3 is a zero of px, then,p-3 = 0⇒(k-1)(-3)2+k(-3)+1=0⇒ (k-1)(10-3k) = 0⇒k = 1 or k=103 Regards! 0 View Full Answer