Q. Find k if one of the zeroes of (k-1)(x2+kx+1) is -3

Dear Student,

We have,px = (k-1)(x2+kx+1), as the given polynomialSince,  -3 is a zero of px, then,p-3 = 0(k-1)(-3)2+k(-3)+1=0 (k-1)(10-3k) = 0k = 1 or k=103

Regards!

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