Q Find the equation of parabola which has its axis along x-axis and which passes through the points (3,2) and (-2,-1). Share with your friends Share 0 Aarushi Mishra answered this The given parabola can also be a translated parabola i.e. A parabola which has been tranlated in the direction of x-axis.Equation of a parabola with axis along x-axis will have it vertex on x-axis say it is Vh,0We know that if a curve is translated to a point x1,y1 with respect to origion then it s equation is given by replacing y by y-y1 and x by x-x1 general equation of parabola is y2=4ax, if it is translated to Vh,0 then its equation becomesy-02=4ax-hy2=4ax-hSince it passes through A3,2 and B-2,-1, therefore it must satisfy these points22=4a3-h and -12=4a-2-h4=4a3-h and 1=4a-2-hDivide these two equations41=4a3-h4a-2-h4=3-h-2-h-8-4h=3-h3h=-11h=-113Put this in 4=4a3-h4a3+113=4a203=1a=320Equation becomesy2=4×320x--113y2=35x+113 0 View Full Answer
