Q.):-  Find the equation of the chord of the circle x 2 + y 2 = r 2 passing through the point (2, 3) farthest from the centre.

Dear Student,
Please find below the solution to the asked query:

We know that infinite chord pass through any point inside circleout of which farthest from centre is the one which is bisected at that point.Hence 2,3 will be mid point of chord and hence line joining centre0,0 and 2,3 will be perpendicular to chord.Slope of  line joining centre and 2,3=m1=3-02-0=32Hence slope of chord=m=-1m1=-23Equation of chord isy-3=-23x-23y-9=-2x+42x+3y=13

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