Q. Find 'x'

110
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Angle(DEA) = 180°-60°=120° Similarly, Angle (BCD) = 130° It is given that angles BAE and ABC are both 90° and ABCDE is a pentagon Sum of all the angles of a pentagon = 540° Therefore, 120° + 130° + 90° + 90° + x = 540° x = 540 - 120 - 130 - 90 - 90 x = 540 - 430 = 110°
  • 1
angle B CD=180-50
              =130 degree
angle A ED=180-60
            =120 degree
therefore,angle[A ED+BCD+E AD+ABC+x]=540
            120+130+90+90+x=540
            430+x=540
            x=110 degree
  • 1
Steps,

180-50 = 130
then,
180-60 = 120
So,
90+90+130+120+X = 540
430+X = 540
540-430 = X
X=110
  • 0
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