Q. Four identical cells each having emf E and internal resistance r are connected in series to form a loop ABCD as shown in figure. Find potential difference across AB and AC. The cell has an emf of 2 V and the internal resistance of this cell is 0.1 ohm. It is connected to resistance of 3.9 ohm. What will be The voltage across the cell? Share with your friends Share 30 Sakshi Kanwar answered this Dear Student The net emf of circuit is 2E as two cells are joined with same polarity and two withdifferentCurrent=net emfnet resistance=2E4r=E2rPotential difference across AB=E-Ir=E-E2r×r=E/2P.D across AC=0-I×2r=-E2r×2r=-EHope this information will clear your doubts about topic. If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible. Regards 52 View Full Answer Shivam Gupta answered this V=E-Ir VacrossAB=E-4E/4r*r=0 V across ac= -27
