# Q) If $\omega \ne 1$ and ${\omega }^{3}=1$, then $\frac{a\omega +b+c{\omega }^{2}}{a{\omega }^{2}+b\omega +c}+\frac{a{\omega }^{2}+b+c\omega }{a+b\omega +c{\omega }^{2}}$ is equal to.

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