Q If the components of air are N2, 78%; O2, 21%; Ar, 0 9% and CO2,0 1% by volume, - Chemistry -

Question

Q If the components of air are N 2 ,   78 % ;   O 2 ,
  21 % ;   A r ,   0 9 %   a n d   C O 2 ,
0 1 %   b y   v o l u m e ,   w h a t   w o u l
d   b e   t h e   m o l e c u l a r   w e i g h
t   o f   a i r ?

Akansha Chauhan · Accepted Answer

Dry air is a mixture of
gases where the molecular weight can be calculated by adding the
weight of each component As shown below:
Wt of each component is calculated by multiplying the % wt of each
component with moleculat wt
(0 78) x (28 g N2/mol) + (0 21) x (32 g
O2/mol)) + (0 009) x (40 g Ar/mol) + (0 001) x (44 g
CO2 /mol)
=
21 84 + 6 72 + 0 36 +0 044 = 28 964 g/mol

molecular weight of air =28
964 g/mol

Q. If the components of air are N 2 , 78 % ; O 2 , 21 % ; A r , 0 . 9 % a n d C O 2 , 0 . 1 % b y v o l u m e , w h a t w o u l d b e t h e m o l e c u l a r w e i g h t o f a i r ?

Q. If the components of air are $N_{2}, 78 %; O_{2}, 21 %; A r, 0.9 % a n d C O_{2}, 0.1 % b y v o l u m e, w h a t w o u l d b e t h e m o l e c u l a r w e i g h t o f a i r ?$