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Q). In the adjoining figure, AB = AC and D is mid-point of BC. Use SSS rule of congruency to show that

(i). $\u25b3ABD\cong \u25b3ACD$

(ii). AD is bisector $\angle A$.

(iii). AD is perpendicular to BC.

(i). $\u25b3ABD\cong \u25b3ACD$

(ii). AD is bisector $\angle A$.

(iii). AD is perpendicular to BC.

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