# Q). In the adjoining figure, AB = AC and D is mid-point of BC. Use SSS rule of congruency to show that (i). $△ABD\cong △ACD$ (ii). AD is bisector $\angle A$. (iii). AD is perpendicular to BC.

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In triangle ABD and triangle ACD,
AB=AC [Given]
BD=CD[D is the mid point of BC]
By SSS congruence criterion,
/\ABD=/\ACD
Since we have proved triangle ABD and triangle ACD congruent their corresponding parts will also be equal.....

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