Q). In the adjoining figure ABCD is a rectangle. Find the area of the shaded region. Share with your friends Share 1 Shruti Tyagi answered this Dear student, There is one correct in the fig AE=10 not 100 cm Area of rectangle ABCD=L×B=CD×AD=18×12=216 cm2Area of ∆ADE=12×AE×AD --[using Area of rt ∆=12×base×height]=12×10×12=10×6=60 cm2Area of ∆EBF=12×EB×BF=12×18-10×12×7=12×8×5=4×5=20 cm2Area of ∆FCD=12×CD×FC=12×18×7=9×7=63 cm2Area of shaded region=Area of rectangle-Area of ∆ADE-Area of ∆EBF-Area of ∆FCD=216 -60 -20 -63 cm2=216-143cm2=72 cm2 Regards -2 View Full Answer Dev Dimple Shah answered this ans- let ae be 10 cm dc 18 cm ad 12 cm fc 7 cm fb 5 cm area of triangle ade 60 cm area of triangle efb 20cm area of triangle dcf 63 cm total area of shaded region = total area of the rectangle - the sum of these triangles i.e. 216-143 =73 0