Q). In the adjoining figure ABCD is a rectangle. Find the area of the shaded region.

Dear student,

There is one correct in the fig AE=10 not 100 cm

Area of rectangle ABCD=L×B=CD×AD=18×12=216 cm2Area of ADE=12×AE×AD                 --[using Area of rt =12×base×height]=12×10×12=10×6=60 cm2Area of EBF=12×EB×BF=12×18-10×12×7=12×8×5=4×5=20 cm2Area of FCD=12×CD×FC=12×18×7=9×7=63 cm2Area of shaded region=Area of rectangle-Area of ADE-Area of EBF-Area of FCD=216 -60 -20 -63 cm2=216-143cm2=72 cm2
Regards

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ans- let ae be 10 cm dc 18 cm ad 12 cm fc 7 cm fb 5 cm
area of triangle  ade 60 cm 
area of triangle efb 20cm
area of triangle dcf 63 cm
total area of shaded region = total area of the rectangle - the sum of these triangles
i.e. 216-143
=73
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