Q). In the figure given below, O is the circumcentre of triangle ABC in which AC = BC. Given that A C B = 56 ° . Calculate (i)  CAB (ii)  OAC.

Hi,

Since AC = Bc so 
angle A = angle B 
So angle A+angle A +angle C = 180 
2angle A = 180-56 = 124
angle A = 62 degree
angle B = 62 degreeNow we know that angle at the center is double that of at circumeferenceangle AOC=2×angleB=  2×62 =124 degreeNow in triangle OACOA= OC = radius so angle OAC = 12180-124= 28 degree angle B = 62 degreeNow we know that angle at the center is double that of at circumeferenceangle AOC=2×angleB=  2×62 =124 degreeNow in triangle OACOA= OC = radius so angle OAC = 12180-124= 28 degree 
Regards  

  • 3
Please find this answer

  • 1
What are you looking for?