Q. In the following figure, DE is parallel to BC. Show that:
Area of traingle (ADC = AEB)
Area of traingle (BOD = COE)

AS WE KNOW DE PARALLEL BC
SO, AR ( BDE)= AR (DEC)
AS THEY LIE ON SAME BASE I.E DE AND BETWEEN THE SAME PARALLELS DE AND BC
NOW ADDING ADE TO BOTH SIDES WE GET,
AR(ABE)=AR(ADC)
(1) PART PROVED
NOW SUBSTRACTING QUADRILATERAL ADOE FROM BOTH SIDES, WE GET
AR(BOD)= AR(COE)
(2) PART PROVED
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