Q. Let coordinates of the points A and B are (5,0) and (0,7) respectively P and Q are the variable points lying on the x and y - axis respectively so that PQ is always perpendicular to the line AB. Then  locus of the point of intersection BP and AQ is 
(A)  x 2   +   y 2   -   5 x   +   7 y   =   0                  (B)  x 2   +   y 2   +   5 x   -   7 y   =   0
(B)  x 2   +   y 2   +   5 x   +   7 y   =   0                  (C)  x 2   +   y 2   -   5 x   -   7 y   =   0

Dear student


Hope it willl clear your doubt. If you have any further doubts you can get back to us.

Regards

  • 2
What are you looking for?