Q) limx→1[x³+2x²+x+1÷ x²+2x+3]1-cos(x-1) ÷ (x-1)² = (ans:( 5/6) 1/2) - Maths - Limits and Derivatives

Question

Q) limx→1 [x³+2x²+x+1÷
x²+2x+3] 1-cos(x-1) ÷ (x-1)²
=
(ans:( 5/6) 1/2)

Swarnika Parul · Answer

After the given solution, proceed by putting Lim h-> 0 we get,
(1+2+1+1/1+2+3)^1/2=√5/√6
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Q) limx→1 [x³+2x²+x+1÷ x²+2x+3] 1-cos(x-1) ÷ (x-1)² = (ans:( 5/6) 1/2)

Q) lim_x→1 [x³+2x²+x+1÷ x²+2x+3] ^{1-cos(x-1) ÷ (x-1)²} _⁼

(ans:( 5/6) ^1/2)