Q no. 12:

12. A platform is pulled with a constant acceleration a A particle is projected from the platform at angle  θ  with the horizontal with respect to the platform as shown in the figure. The value of tan θ such tha particle again come to the starting point on the platform is  (a=5 m/s2): use g = 10 m/s2

(A) 4              (B) 6              (C) 2              (D) 3
 

Dear student,

Let the particle be projected with velocity u making an angle θ with the platformSo horizontal distance covereds=ucosθ×tDistance covered by the platform S=1/2at2Time of flight t=2usinθgAs the particle returns to the platform, so ucosθ×t=1/2at2or t=2ucosθ/aor 2usinθg=2ucosθaor tanθ=ga
 
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