Q.no.12

Q.no.12 'l here is no change in the molarity of S04 ion. There is a change in the molarity of S04.- ion. A current strength of 96.5 A is passed for 10 s through 1 L of a solution of Q. I M aqueouS CuS04. Calculate the pH of the solution. I F of electricity is passed through 10 L Ofa solution of aqueous.solution ofNaC\. - -Calculate-the pwo f the solution. Wbat weight of Ni is plated out in an electrolysis ofaquƩous NiS04 solution that is takes place to deposit 2 g of Ag in a silver coulometer that is arranged in series with NiS04 electrolytic cell. [Atomic weight of Ag = 107.8 amu, atomic weight of Ni = 58.7 amul 1. 0.2938 g 2. ANSWER KEY (a) 22.68 g (b) 4.428 L of02, (c) 1

According to Faraday II law,Weight of AgWeight of Ni = Equivalent mass of AgEquivalent mass of NiEquivalent mass = Molar massvalency2Weight of Ni = 107.8/158.7/2Weight of Ni =0.5445 g 

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