Q no 20 @22 Q20. Given that PR =PS, RQ = PS and ∠ SPT =102°, find the value of unknown angle ∠ RPQ from the given figure. Q22. AB is the diameter of a given circle with centre O. If PA = PB and ∠ PAC = 20°, find the value of ∠ PAB and ∠ ABC. Share with your friends Share 0 Anuradha Sharma answered this Hi, 20) Here PR = PS so angle PRS = angle PSR also PR = QR so angle RPQ = angle PQR so in triangle PQS using external angle theorem, 102 = angle PQR+angle PSQ=angle RPQ + angle PRSalso using external angle theorem angle PRS=angle RPQ + angle PQR =2angle RPQ so 102 =angle RPQ + angle PRS=3 angle RPQangle RPQ= 34 degreePlease send single query in a thread 0 View Full Answer