Q no 4 A block of mass 2 kg is placed on the floor The coefficient of static - Science - Friction

Question

Q no 4 A block of mass 2 kg is placed on the floor The coefficient
of static friction between the two surfaces is 0 4 A horizontal
force of 2 5 N is applied on the block as shown The force of
friction between the block and the floor is
(A) 7 84 N
(B) 2 50 N
(C) 6 45 N
(D) 13 34 N

Anshu Agrawal · Accepted Answer

Dear student,

Maximum static frictional force=μmgfmax=0
4×2×9 8=7
84NSince the applied force is less than the frictional force,the frictional force is equal to the applied force= 2
5NThis is due the reason that frictional force is self adjusting force

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Q no 4. A block of mass 2 kg is placed on the floor. The coefficient of static friction between the two surfaces is 0.4. A horizontal force of 2.5 N is applied on the block as shown. The force of friction between the block and the floor is (A) 7.84 N (B) 2.50 N (C) 6.45 N (D) 13.34 N

Q no 4. A block of mass 2 kg is placed on the floor. The coefficient of static friction between the two surfaces is 0.4. A horizontal force of 2.5 N is applied on the block as shown. The force of friction between the block and the floor is
(A) 7.84 N
(B) 2.50 N
(C) 6.45 N
(D) 13.34 N