Q no. 6 Find the equation of the perpendicular bisector of the line segment joining the points (1, 1) and (2, 3). Share with your friends Share 0 Varun Rawat answered this We know that slope of line segment joining the points x1, y1 and x2, y2 isslope = y2 - y1x2 - x1Now, slope of the line segment joining the points 1,1 and 2,3 ism1 = 3 - 12 - 1 = 2Now, slope of the line segment ⊥ to the line segment joining the points 1,1 and 2,3 ism2 = -1m1 = -12Now, mid point of the line segment oining the points x1, y1 and x2, y2 is x1+x22, y1+y22.So, mid-point of the line segment joining the points 1,1 and 2,3 is 1 + 22, 1 + 32 = 32, 2Now, equation of the line segment passing through x1, y1 and having slope m isy - y1 = mx-x1So, equation of the line segment passing through 32, 2 and having slope -12 is,y - 2 = -12x - 32⇒2y - 4 = -x + 32⇒x + 2y = 4 + 32⇒x + 2y = 112⇒2x + 4y = 11This is the required equation of the ⊥ bisector of the line segment joining the points 1,1 and 2,3. 3 View Full Answer Akshat Agarwal answered this Hmmm -2
