# Q no9 ans is option b A tangent to the ellipse 4x2+9y2=36 is cut by the tangent at the extremities of the major axis at T and T'. The circle on TT' as diameter passes through the point  (A) (0-$\sqrt{}$5)                            (B) (  $\sqrt{}$  5, 0 ) (C) (0,0)                                    (D) (3,2)

Hi,
4x2+9y2=36
x2/9+y2/4 = 1
Now

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