Q. On adding 1mLsolution of NaCl to 10 mL gold sol in presence of 0.25 g starch so that coagulation is just prevented what will be gold number of starch.
(1) 0.25
(2) 2.5
(3) 250
(4) 0.025
Dear Student,
0.25 g of starch needed to prevent coagulation of 1 ml of NaCl to 10 ml gold solution.
So the amount of starch is 0.25g = 250 mg. Hence gold number is 250.
Hence, 3 is correct
​
Regards​,
0.25 g of starch needed to prevent coagulation of 1 ml of NaCl to 10 ml gold solution.
So the amount of starch is 0.25g = 250 mg. Hence gold number is 250.
Hence, 3 is correct
​
Regards​,
