Q). Please explain the paragraph in more simple sentences.
Two cases arise here, the first one is that when a single stranded DNA or RNA is tagged with a radioactive probe is allowed to hybridise with its complementary single stranded molecule with no mutation in gene will easily hybridise because they are complementary to each other, Due to the presence of radioactive probe which is attached to the gene will be detected in autoradiography.
In second case when single stranded DNA or RNA tagged with radioactive probe will not hybridise with its complementary gene because they are mutated and after mutation the sequence of gene changes means
the nitrogenous bases have been changed due to mutation, so it will not hybridise.
Autoradiography detects radioactive probe tagged in the gene and in the second case since there is no
complementarity due to mutation therefore it do not hybridises and is not detected in autoradiography.

Dear student, 
The answer given by our expert is in the most simplest language possible. However, I have tried to be more explanatory. Please find below the solution:

Two cases arise during hybridisation step-
  • when a single stranded DNA or RNA tagged with a radioactive probe is allowed to hybridise with its complementary single stranded molecule with no mutation in gene. Here, the probe will easily hybridise because they are complementary to each other and there is no mutation in the complementary gene. Due to the presence of radioactive probe which is attached to the gene, the result will be detected by autoradiography on a photographic film..
  • When single stranded DNA or RNA tagged with radioactive probe will not hybridise with its complementary gene because they are mutated and after mutation the sequence of gene changes means the nitrogenous bases have been changed due to mutation, so it will not hybridise and hence, these regions will not appear on the photographic film after autoradiography.
Autoradiography detects radioactive probe tagged in the gene and in the second case since there is no complementarity due to mutation therefore it do not hybridises and is not detected in autoradiography.

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