Q. Spin magnetic moment of . Hence number of upaired electrons and value of n respectively are
- 4,2
- 2,4
- 3,1
- 0,2
Dear Student,
Magnetic moment is =BM
According to given data,
=
Squaring on both sides,we get
⇒ n(n+2) = 24
⇒ n(n+2) = 24
⇒ n = 4
Thus 4 unpaired electron in the X element
The X element have atomic number 26 is given.
Atomic number 26 ,element have electronic configuration is [Ar] 4S23d6 and It has 6 electrons in the valence shell
So the value of n = 6-4=2
Thus, Xn+ = Fe2+
Fe2+has four unpaired electrons.
So the correct answer is (1).
Regards
Magnetic moment is =BM
According to given data,
=
Squaring on both sides,we get
⇒ n(n+2) = 24
⇒ n(n+2) = 24
⇒ n = 4
Thus 4 unpaired electron in the X element
The X element have atomic number 26 is given.
Atomic number 26 ,element have electronic configuration is [Ar] 4S23d6 and It has 6 electrons in the valence shell
So the value of n = 6-4=2
Thus, Xn+ = Fe2+
Fe2+has four unpaired electrons.
So the correct answer is (1).
Regards