Q.The correct expression representing the relation between thevan't Hoff factor (i) and the degree of dissociation (α) of a weak electrolyteMaNbis

  • A) α=ia+ba+b-1
  • B) α=ia+ba+b+1
  • C) α=i-1a+b-1
  • D) α=i-1a+b+1

Q.The correct expression representing the relation between thevan't Hoff factor (i) and the degree of dissociation (α) of a weak electrolyteMaNbis

  • A) α=ia+ba+b-1
  • B) α=ia+ba+b+1
  • C) α=i-1a+b-1
  • D) α=i-1a+b+1

Dear student
Please find the solution to the asked query:


The electrolyte given is MaNb
So dissociation of the electrolyte gives:
Given that Vant Hoff factor =iDegree of dissociation=αThus MaNbaMb+ + bNa-1-α         αa          αbThusTotal amount of species = 1+(a+b-1)αVant Hoff factor i = 1+(a+b-1)α1           α   =i-1(a+b-1)

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