Q. The following figure shows the cross-section ABCD of a swimming pool which is trapezium in shape.
If the width DC, Of the swimming pool is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at deepest end is 2.4 m find its area of the cross-section.
As shown in the figure the depths of the swimming pool are parallel.
Length of the shorter parallel side = 0.8m
Length of the longer parallel side = 2.4m
The width of the swimming pool acts as the height of the trapezium
Height of the trapezium = 6.4m
area of trapezium = ½(sum of the parallel sides)h
= (2.4 + 0.8)(6.4)(1/2)
= (3.2)(3.2)
= (10.24)
The are of the cross section of the swimming pool is 10.24 m2.
Length of the shorter parallel side = 0.8m
Length of the longer parallel side = 2.4m
The width of the swimming pool acts as the height of the trapezium
Height of the trapezium = 6.4m
area of trapezium = ½(sum of the parallel sides)h
= (2.4 + 0.8)(6.4)(1/2)
= (3.2)(3.2)
= (10.24)
The are of the cross section of the swimming pool is 10.24 m2.
