Q.):-  The potential of the electrochemical cell based on the reaction given below is 1.1 V at $25°C.$
$Z{n}_{\left(s\right)}+C{u}_{\left(aq\right)}^{2+}\rightleftharpoons Z{n}_{\left(aq\right)}^{2+}+C{u}_{\left(s\right)}$ .
What will be potential of the cell at $25°C$ if the concentration of $Z{n}^{2+} and C{u}^{2+}$ ions each is 0.1 M?
A) 1.10      B)  0.10        C)  -1.10      D)  -0.10

See Priyanshi, the magnitude of the electrode potential is always dependent on :- 1) Nature of the electrodes
                                                                                                                                   2)"*No.of Ions in both the solution*" and
                                                                                                                                   3)Temperature.
You knw that right?
I made the star for the reason that ions in both the solutions is equal thus there will be no change in the potential of the cell. If it was different then the potential would differ...so as both the solutions have same number of moles thus the potential of the cell will remain unchanged and will be 1.1V only. Hope it helps you...^_^