Q. The sum of the digits of a two digit number is 9. If the digits are reversed then the number is increased by 45. Find the number. Share with your friends Share 0 Amit Shukla answered this Dear Student, Let the two digits be x and y, where x is at tens place and y is at ones place;so the no. is (10x+y) and, it is also given that the sum of digits is 9 so;x+y=9 ---(1)now, if the digits are reversed, then the new no. will be 10y+xAccording to the question;the new number will become 45 more then the original one;therefore,10x+y+45=10y+x10x-x+y-10y=-459x-9y=-45substituting (from (1) , y=9-x), we get9x-9(9-x)=-459x-81+9x=-4518x=-45+8118x=36x=2and,y=9-x=9-2=7so the number required is;10×2+7=27 hope, you will find this answer helpful. 0 View Full Answer Rituraj answered this i dont know sorry 2 Srishty Kapur answered this 36 is the original number 63 is reversed number -1 Anamitra Roy answered this Let the digits be x and y where x is the ten's place digit and x+y=9[as per given question] Therefore no. is 10x+y Digits are reversed so new no. is 10y+x A.T.P 10x+y+45=10y+x 10x+(9-x)+45=10(9-x)+x [x+y=9 so y=9-x] Solve equation x=2 therefore no. is 27 1
