Q.There are two temples, one on each bank of a river, just opposite to each other. One temple is 50m high. From the top of this temple, the angles of depression of the top &the foot of the other temple are 300 & 600 respectively. Find the width of the river and the hight of the other temple.

Dear Student!

Here is the answer to your query.

 

 

Let AB and CD be the two temples and BC be the width of the river.

Then ∠ ADE = 30° and ∠ ACB = 60°

Given : AB = 50 m

 

In Δ ABC

 

In Δ AED

 

Hence the width of the river is 28.867 m and height of the other temple is 33.33 m

 

Cheers!

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Thanks sir...

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