Q.  Two capacitors Of capacitance 600 pF and 900 pF are connected in series across a 200 V supply. Calculate (i) the effective capa.citance of the combination, (ii) the pd across each  capacitor and (iii) the total charge stored in the system.

Dear Student

C1=600pF =600×10-12FC2=900pF =900×10-12FAs capacitors are connected in series so total capacitance will be1C=1C1+1C2C=C1C2C1+C2=600×10-12×900×10-12600×10-12+900×10-12=540000×10-241500×10-12=360×10-12FIn series connection , charge on each capacitor is same.Therefore charge q =CVq =360×10-12F×200 =720×10-10C =TOTAL CHARGE STORED P.D. across 600pF capacitor =qC1 =720×10-10C 600×10-12F=120 VP.D. across 900pF capacitor =qC2 =720×10-10C 900×10-12F=80 V
Regards

  • 25
What are you looking for?