Q XeF2 is linear despite the fact it involves sp2d hybridisation Explain Q Dp you expect P-Cl - Chemistry - Chemical Bonding and Molecular Structure

Question

Q   X e F 2   i s   l i n e a r   d e s p i t e
  t h e   f a c t   i t   i n v o l v e s
  s p 2 d   h y b r i d i s a t i o n   E x p l a i
n Q   D p   y o u   e x p e c t   P - C l
  b o n d   e n e r g y   t o   b e   s a
m e   i n   P C l 3   a n d   P C l 5 +  
E x p l a i n   y o u r   a n s w e r

Ravjot Kaur · Accepted Answer

Dear student

16
XeF2
Xe is the central atom, which has 8 valence electrons Two atoms of
F combine with two electrons of Xe to form 2 bond pairs The
remaining 6 electrons remain as 3 pairs of lone pairs around the
central atom
Thus total electron pairs= 3lone pairs+ 2bond pairs
= 5 electron pairs
But hybridisation is sp3d, but shape is linear, as the
lone pairs occupy the equatorial positions

<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_59fac1d943416%20jpg"
style="width: 186px; height: 237px;">
please post remaining questions separately
Regards

Q . X e F 2 i s l i n e a r d e s p i t e t h e f a c t i t i n v o l v e s s p 2 d h y b r i d i s a t i o n . E x p l a i n . Q . D p y o u e x p e c t P - C l b o n d e n e r g y t o b e s a m e i n P C l 3 a n d P C l 5 + . E x p l a i n y o u r a n s w e r .

$Q . X e F_{2} i s l i n e a r d e s p i t e t h e f a c t i t i n v o l v e s s p^{2} d h y b r i d i s a t i o n . E x p l a i n . Q . D p y o u e x p e c t P - C l b o n d e n e r g y t o b e s a m e i n P C l_{3} a n d P C l_{5^{+}} . E x p l a i n y o u r a n s w e r .$