Login

Q1

​1. Two blocks of masses 20 kg and 50 kg are lying on the horizontal floor (coefficient of friction  μ  =0.5). initially staring is stretched and blocks are at rest. Now two forces 300 N and 150 N is applied on two blocks as shown in figure. The acceleration of 20kg block is 2.5 K m/s2. Find the value of K. 


​

Dear Student,



Regards.

  • 62
View Full Answer
  Let the tension in the rope be `T` and accleration of masses be `a`. The frictional force acting on 50kg block is 250N. And that on 20 kg block is 100N. Therefore we can say that, 300 - (250 + T) = 50a, and150 + T - 100 = 20a from here we get a = 100/70 or 1.4285 = 2.5 k , so k = 4/7
  • -41
What are you looking for?