Q11. If x = 1 + log a b c , y = 1 + log b c a , z = 1 + log c a b prove that xyz = xy + yz + zx Share with your friends Share 0 Vipin Verma answered this x =1+logabc , y = 1+logbca , z = 1+logcabFrom the property of logarithm , we have logpq =logsplogsq , logss = 1As xy + yz + zx = xzyOr 1x+1y+1z =1And x =1+ logabc , y = 1+logacalogab , z = 1+logaablogacSo 1x+1y+1z= 11+ logabc + logab logab + logaca + logac logac + logaab= logaa logaa+ logabc + logab logab + logaca + logac logac + logaab= logaa + logab+ logac logaabc= logaabc logaabc = 1 (hence proved) 13 View Full Answer