Q12 part IV experts give solution 12. Solve foc
(i) 2 cos
(ii) cos
1
(iii) sin (x + —
(iv) cos (2x-3(PÅ'J
2
(v) 2 cos (3x= 150)
= I(vi) tan2
(vii) 3 tan2 (2K — 200) =
(viii) cos
2
(ix) sin2 x + sin2 300 = I
(x) cos2 300 + cos2 x = 1
(xi) cos2 300 + sin2 2r = 1
(xii) sin2 600 + cos2 (3x — 90) = I
13. If 4 cos2 x = 3 and x is an acute angle;fil
the value of :
(iii) cos 3x
(ii) cos2 x + coe x
(iv) sin 2.x
_ 01
14. In A ABC, LB = 900, = y units,
units, AC = 2 units and angle A f,